(x^2-9)/ln(x-2)

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Solution for (x^2-9)/ln(x-2) equation: 


D( x )

x-2 <= 0

ln(x-2) = 0

x-2 <= 0

x-2 <= 0

x-2 <= 0 // + 2

x <= 2

ln(x-2) = 0

ln(x-2) = 0

ln(x-2) = ln(e^0)

x-2 = e^0

x-e^0-2 = 0

x-3 = 0 // + 3

x = 3

x in (2:3) U (3:+oo)

(x^2-9)/ln(x-2) = 0

(x^2-9)/ln(x-2) = 0 // * ln(x-2)

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { 3} 

x in { -3} 

x belongs to the empty set

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